Question 660783


{{{x+15y=1}}} Start with the given equation.



{{{15y=1-x}}} Subtract {{{x}}} from both sides.



{{{15y=-x+1}}} Rearrange the terms.



{{{y=(-x+1)/(15)}}} Divide both sides by {{{15}}} to isolate y.



{{{y=((-1)/(15))x+(1)/(15)}}} Break up the fraction.



{{{y=-(1/15)x+1/15}}} Reduce.



So the equation {{{y=-(1/15)x+1/15}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/15}}} and the y-intercept is {{{b=1/15}}} note: the y-intercept is the point *[Tex \LARGE \left(0,\frac{1}{15}\right)]