Question 660689
{{{abs(a) = a}}} if {{{a>=0}}}


So if {{{a>=0}}}, then 


{{{ a <= abs(a) }}}


becomes


{{{ a <= a }}}


which is certainly true.


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{{{abs(a) = -a}}} if {{{a<0}}}


So if {{{a<0}}}, then 


{{{ a <= abs(a) }}}


becomes


{{{ a <= -a }}}


which is also true (since 'a' is negative, '-a' is positive)

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These two cases exhaust all possibilities


So this proves that {{{ a <= abs(a) }}} is always true for any value of 'a'.


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