Question 59935
The given expression is: 


rs(x - 1) = x - 3


We remove the radical on the left hand side by squaring both sides of the given expression.


That is:


(x - 1) = (x - 3)^2 


Expanding the right hand side by using the formula (a - b)^2, we get:


(x - 1) = x^2 - 6x + 9 


Adding 1 - x to both sides of the above equation, we get:


x^2 - 6x + 9 + 1 - x = 0 


x^2 - 7x + 10 = 0  [Adding the like terms, we get]


Using the method of Factorization, we get: 


x^2 - 5x - 2x + 10 = 0 


x(x - 5) - 2(x - 5) = 0


(x - 2)(x - 5)  = 0 


Thus, the values of x are 2 and 5.