Question 660396


{{{(w-3)/2+(w-4)/3=12}}}...to eliminate denominator, find LCD...for {{{2}}}, {{{3}}}, LCD is {{{6}}} 



{{{(w-3)3/2*3+(w-4)*2/3*2=12}}}


{{{(3w-9)/6+(2w-8)/6=12}}}.....both sides multiply by {{{6}}}


{{{(3w-9)*6/6+(2w-8)*6/6=12*6}}}


{{{(3w-9)*cross(6)/cross(6)+(2w-8)*cross(6)/cross(6)=72}}}


{{{3w-9+2w-8=72}}}


{{{5w-17=72}}}


{{{5w=72+17}}}


{{{5w=89}}}


{{{w=89/5}}}


{{{w=17.8}}}