<PRE><B>Question 659764</B>
x = integer
2x^2-5x=63
2x^2 - 5x - 63 = 0
(   +   )(   -  )  Mixed sign as the - 63
multiples of 63: 3,21; 7,9; 63,1
Thinking 2 times one of these multiples, minus the other member of the pair needs to give 5, I use 7,9.  
Where 2x7=14-9=5  
Since the 5 is negative, apply the minus to the 7.
(2x + 9)(x - 7)

x - 7 = 0
x=7  OK
2x+9=0
2x=-9
x=-9/2 NO

The integer is 7</PRE>