Question 659876
{{{7x^2+3x+8=0}}}..use quadratic formula to solve for {{{x}}}


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} ....{{{a=7}}}, {{{b=3}}} and {{{c=8}}}


{{{x = (-3 +- sqrt( 3^2-4*7*8 ))/(2*7) }}}


{{{x = (-3 +- sqrt( 9-224 ))/14 }}}


{{{x = (-3 +- sqrt( -215 ))/14 }}}


{{{x = (-3 +- 14.7i)/14 }}}


{{{x = -3/14 +- 14.7i/14 }}}


{{{x = -0.214 +- 1.05i }}}.......means, there is {{{no}}} {{{real}}} {{{solutions}}}, only


complex solutions:


{{{x = -0.214 + 1.05i }}}

or

{{{x = -0.214 - 1.05i }}}




{{{ graph( 600, 600, -5, 5, -2, 10, 7x^2+3x+8) }}}