Question 59821
THE DIAGONAL OF A SQUARE 20 FOOT RING IS SOLVED BY THE FORMULA A^2+B^2=C^2 WHERE THE A & B SIDES ARE 20 FEET. THUS THE DIAGONAL (C) IS
20^2+20^2=C^2
400+400=C^2
800=C^2
C=SQRT800
C=28.28 FEET IS THE DIAGONAL ACROSS THE RING