Question 659156

please help me solve this problem, i can't understand it. One side of a triangle is four less than twice the shortest side. The third side is six more than the shortest side. Find the measure of each side if the perimeter of a triangle is 34 m.


Let length of shortest side be S
Then second side = 2S - 4
Third side = S + 6


Since perimeter = 34m, then: S + 2S - 4 + S + 6 = 34


4S + 2 = 34


4S = 34 - 2


4S = 32


S, or smallest side = {{{32/4}}}, or {{{highlight_green(8)}}} m


Second side = 2(8) - 4, or {{{highlight_green(12)}}} m


Third side = 8 + 6, or {{{highlight_green(14)}}} m


Check to see if the measures of the 3 sides sum to 34 m


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