Question 658835
It takes Myline twice as long as Jeana to do a certain piece of work. Working together, they can finish the work in 6 hours. How long would it take Jeana to do it alone?
<pre>
Their combined rate is 1 job per 6 hours or {{{(1_job)/(6_hours)}}} or {{{1/6}}}{{{job/hour}}}

Jeana's rate is 1 job per x hours or {{{(1_job)/(x_hours)}}} or {{{1/x}}}{{{job/hour}}}

Myline's rate is 1 job per 2x hours or {{{(1_job)/(2x_hours)}}} or {{{1/(2x)}}}{{{job/hour}}}

The equation comes from {{{(matrix(4,1,

"Jeana's", rate, in, "jobs/hour"))}}} + {{{(matrix(4,1,

"Myline's", rate, in, "jobs/hour"))}}} = {{{(matrix(5,1,

Their, combined, rate, in, "jobs/hour"))}}}

                                     {{{1/x}}} + {{{1/(2x)}}} = {{{1/6}}}

Multiply through by LCD = 6x and solve.  You'll get 9 hours.

Edwin</pre>