Question 658760
given: the volume of a rectangular pyramid is {{{160ft^3}}}

the length {{{L=12ft}}} 

the width {{{W=4ft}}} 


for a pyramid with width {{{W}}}, length {{{L}}} and height {{{h}}}, the volume,
 
{{{V}}} of the pyramid will be:

{{{V=(1/3)WLh}}}.......solve for {{{h}}}

{{{3V=WLh}}}

{{{3V/WL=h}}}..........plug in given values

{{{h=3(160ft^3)/(4ft*12ft)}}}

{{{h=cross(3)(160ft^3)/(4ft*cross(12)4ft)}}}

{{{h=(cross(160)40ft^3)/(cross(4)ft*4ft)}}}


{{{h=(cross(40)10ft^cross(3))/(cross(4)cross(ft^2))}}}

{{{highlight(h=10ft)}}}