Question 658752
Let {{{ t }}} = time for 1st trip
Let {{{ d }}} = distance from base
Equation for 1st trip
(1) {{{ d = 300t }}}
Equation for 2nd trip:
(2) {{{ d = 250*( t + 1/4 ) }}}
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Substitute (1) into (2)
(2) {{{ 300t = 250*( t + 1/4 ) }}}
(2) {{{ 300t = 250t + 250/4 }}}
(2) {{{ 6t = 5t + 5/4 }}}
(2) {{{ t = 5/4 }}}
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(1) {{{ d = 300*(5/4) }}}
(1) {{{ d = 75*5 }}}
(1) {{{ d = 375 }}}
It flew 375 mi from base
check:
(2) {{{ 375 = 250*( t + 1/4 ) }}}
(2) {{{ 3 = 2*( t + 1/4 ) }}}
(2) {{{ 3 = 2t + 1/2 }}}
(2) {{{ 2t = 5/2 }}}
(2) {{{ t = 5/4 }}}
OK