Question 658689
(7^-4)^-2 = 7^(-4*-2) = 7^8


(7^4)^-2 = 7^(4*-2) = 7^-8


So "7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power" becomes {{{7^8*7^(-8) = 7^(8+(-8)) = 7^0 = 1}}}