Question 658604

man's age + his wife's age=63.
He is twice as old as his wife was when he was his wife's present age.

All I can get is      he =x   she=y

x=2(y-[x-y])      x+y=63

What do I do now?


x + y = 63 ----- x = 63 - y ------ eq (i)


x = 2[y – (x – y)]
x = 2(y – x + y)
x = 2(2y - x)
x = 4y – 2x 
x + 2x – 4y = 0 
3x - 4y = 0 ------ eq (ii)


3(63 - y) - 4y = 0 -------- Substituting 63 - y for x in eq (ii) 
189 - 3y - 4y = 0
- 7y = - 189


y, or wife's age = {{{(- 189)/- 7}}}, or {{{highlight_green(27)}}}


Now substitute 27 for y in eq (i) and you'll find man's age.


You can also do your own check!!


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