Question 658525
{{{4x^2+4x-4=0}}}

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}...note that {{{a=4}}}, {{{b=4}}} and {{{c=-4}}}

{{{x = (-4 +- sqrt( 4^2-4*4*(-4) ))/(2*4) }}}


{{{x = (-4 +- sqrt( 16-16(-4) ))/8 }}}


{{{x = (-4 +- sqrt( 16+64 ))/8 }}}


{{{x = (-4 +- sqrt( 80 ))/8 }}}


{{{x = (-4 +- 8.9)/8 }}}


solutions:

{{{x = (-4 + 8.9)/8 }}}


{{{x = (4.9)/8 }}}


{{{highlight(x = 0.6125)}}}

or

{{{x = (-4 -8.9)/8 }}}


{{{x = (-12.9)/8 }}}


{{{highlight(x = -1.6125)}}}