Question 59765
1. {{{ x = 3y - 2 }}}
2. {{{ 2x + 4y =16 }}}
Substitute equation 1 into equation 2
{{{ 2(3y-2) + 4y = 16 }}}
Distribute
{{{ 6y - 4 + 4y = 16 }}}
combine like terms
{{{ 10y - 4 = 16 }}}
add 4 to both sides
{{{ 10y = 20 }}}
divide by 10
{{{ y = 2 }}}


Substitute y=2 back into equation number one
{{{ x = 3y - 2 }}}
{{{ x = 3(2) -2 }}}
{{{ x = 6 - 2 }}}
{{{ x = 4 }}}


Your solution is 
(4,2)