Question 658176
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If you have tried everything, then you certainly don't need our help.  By definition, everything includes the one right thing.  Therefore you already have the answer.  But on the off chance that you haven't actually tried everything, I'd be delighted to help you as soon as you share just one of the things you have tried.

Oh, and by the way, the rule is one question per post.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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