Question 658079
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Hi,
the sum of two numbers{{{highlight(x)}}}& {{{highlight(y)}}} is 19 and the sum of their squares is 221
Question states*** 
  x + y = 19  0r  {{{y = 19-x}}}
x^2 + y^2 = 221
 x^2 + (19-x)^2 = 221
 x^2 + 361-38x + x^2 = 221
  2x^2 - 38x  + 140 = 0
   x^2 - 19x + 70 = 0
factoring
(x - 14)(x-5) = 0
(x - 14)= 0,  x = 14   and y = 5
0r(x-5) = 0,  x =  5   and y = 14
numbers are 5 and 14