Question 658044
Find the equation of the ellipse with vertices (0, -1) and (12, -1) and minor axis of length 6
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Form: (x-h)^2/a^2 + (y-k)/b^2 = 1
h = 6, k = -1 ; a = 6 ; b = 3
Equation:
(x-6)^2/36 + (y+1)/9 = 1
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And:
What is the equation of the axis of symmetry of the parabola whose equation is 2(y - 2) = (x + 3)2?
Vertex is at (-3,2)
Axis of symmetry is x = -3
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Cheers,
Stan H.
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x = -3 
x = 3 
x = 0 
y = -2 
y = 2