Question 657944
{{{4^(2y) + 4^(2y-1) = 4}}}

 since {{{4^(2y)/4}}} we have

{{{4^(2y) + 4^(2y)/4 = 4 }}}...both sides multiply by {{{4}}}

{{{4*4^(2y) + 4*4^(2y)/4 =4* 4 }}}

{{{4*4^(2y) + 4^(2y) = 16 }}}

{{{4^(2y)(4 + 1) = 16 }}}

{{{5*4^2y = 16 }}}

{{{4^(2y) = 16/5 }}}


{{{y = (4*log(2)-log(5))/4*log(2) }}}


{{{y = (4* 0.30102999566-0.69897000434)/4*0.30102999566) }}}


{{{y = (1.20411998264-0.69897000434)/1.20411998264) }}}


{{{y = (0.5051499783)/1.20411998264) }}}


{{{highlight(y =0.42)}}}

{{{cartoon( 
  number_line( 600, -10, 10,  0, 0.42 ) ) )}}}