Question 657944
how can i find the value of y?
4^2y + 4^(2y-1) = 4
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{{{4^(2y-1)*(4 + 1) = 4}}}
{{{4^(2y-1) = 4/5}}}
(2y-1)*log(4) = log(0.8)
2y-1 = log(0.8)/log(4)
y = (log(0.8)/log(4) + 1)/2