Question 657773
Find a formula for the quadratic function whose graph has vertex(2,-2) and y-intercept of -5
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standard form of equation for a parabola:{{{ y=A(x-h)^2+k}}}, (h,k)=(x,y) coordinates of the vertex
For given parabola:
{{{y=A(x-2)^2-2}}}
solve for A using coordinates of y-intercept (0,-5)
-5=A(0-2)^2-2
-5=4A-2
4A=-3
A=-3/4
equation of given quadratic function:
{{{y=(-3/4)(x-2)^2-2}}}