Question 657390
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Hi,
{{{Q(t) = Q[0]e^(-kt)}}}  where  k = .00012 (assume this is the k You are using)
{{{Q(t) = 2e^(-.00012t)}}} 
{{{Q(5760) = 2e^(-.00012*5760)= 1.0019g}}}  
{{{Q(11520) = 2e^(-.00012*11520)= .502g}}} 
{{{Q(23040) = 2e^(-.00012*23040)= .126g}}}