Question 657395
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Hi,
(4a-3)^2
(4a-3)(4a-3) = 16a^2 - 24a + 9
When using FOIL, the 'middle'term is the sum of the outside and inside products
F	First terms    16a^2
O	Outside terms  -12a
I	Inside terms   -12a
L	Last terms  (-3)(-3) = 9