Question 656253
what type of conic section is given by the following equation ?
(x-2)^2/2^2-(y+1)^2/5^2=1
This is a hyperbola with horizontal transverse axis. (x-term listed in front of y-term)
Its standard form of equation: (x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of the center.
Given equation:{{{(x-2)^2/4-(y+1)^2/25=1}}}
center:(2,-1)