<PRE><B>Question 656913</B>
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In order to have an 80 average for 6 tests, the total of her scores must be 6 times 80.  Add up the scores she has and subtract from 6 times 80.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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