Question 59699
How do you evalute (((f(x)=(x^2-6)/(3x)}}}; f(n-3)?
Replace all of the x's with n-3 and simplify:
{{{f(n-3)=((n-3)^2-6)/(3(n-3))}}}
{{{f(n-3)=(n^2-6n+9-6)/(3(n-3))}}}
{{{f(n-3)=(n^2-6n+3)/(3n-9)}}}
Happy Calculating!!!