Question 656788
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In each case you have two expressions in *[tex \LARGE x] that are equal to y.  Things equal to equal things are in turn equal to each other.  Set the two RHS expressions equal to each other and solve for *[tex \LARGE x].  Then substitute back to find the value for *[tex \LARGE y]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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