Question 656768
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If she had *[tex \LARGE x] quarters, then she must have had *[tex \LARGE 40\ -\ x] dimes.  Quarters are worth 25 cents each, so the total value of her quarters must have been *[tex \LARGE 25x] cents.  Likewise the total value of her dimes must have been *[tex \LARGE 10(40\ -\ x)] cents.  The total amount she had, namely 775 cents, is equal to the sum of the value of her quarters and the value of her dimes:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 25x\ +\ 10(40\ -\ x)\ =\ 775]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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