Question 656745

{{{3}}}consecutive even numbers would be {{{x}}}, {{{x+2}}}, and {{{x+4}}} 

Two times the square root of the sum of 3 consecutive even numbers is {{{24}}}:


the sum of 3 consecutive even numbers is: {{{x+(x+2)+(x+4)}}}...->...{{{3x+6}}} 

two times the square root of the sum is {{{24}}}: {{{2*sqrt(3x+6)=24}}}
 

{{{2*sqrt(3x+6)=24}}}...solve for {{{x}}}

{{{cross(2)*sqrt(3x+6)=cross(24)12}}}

{{{sqrt(3x+6)=12}}}....both sides raise to power of two

{{{(sqrt(3x+6))^2=12^2}}}

{{{3x+6=144}}}

{{{3x=144-6}}}

{{{3x=138}}}

{{{highlight(x=46)}}}...first number


{{{highlight(x+2=48)}}}.....second number


{{{highlight(x+4=50)}}}......third number