Question 656682
	
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Hi,
How many gallons{{{highlight(9-x)}}} of 15% alcohol solution and 60% alcohol solution{{{highlight(x)}}} must be mixed 
to get <u>9 gallons</u> of 30% alcohol solution?
Mixing...............
 .60x + .15(9-x) = .30·9gal
       .45x = .15·9
          x = 3gal, amount of the 60% alcohol solution. 6gal of 15% alcohol solution
and...
{{{.6*3 + .15*6 =  1.8 + .9 = .3*9 = 2.7}}}