<PRE><B>Question 656351</B>
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If he wants 20 on each side including the corners, then there must be 18 on each side that are NOT on the corners.  4 times 18 plus the 4 that are on the corners, or more simply put 19 X 4.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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