Question 656311
A (3,-2)= (x1,y1)

B (-4,-1)=(x2,y2)

If Equation of a line is 
y = mx + c1  
then the equation of perpendicular line will be  
y = (-1/m)x + c2

So if you find the slope of the first line we get the slope of the perpendicular line 

slope = (y2-y1)/(x2-x1)

y2-y1 = -1-(-2) = 1
x2-x1 = -4-3 = -7

slope m = (y2-y1)/(x2-x1) = -1/7

so the slope of perpendicular line is -1/m = -1/(-1/7) = 7

perpendicular line equation is y = 7x + c2

to find intercept  substitute point A since line passes through A

-2 = 7 * 3 + c2 

c2 = -2 -21 = -23

slope = 7

y intercept = -23