Question 656197
 If I draw 3 cards at once (from standard deck 52, no replacement) find the following probabilities:
a) at least one face card
P(at least one face) = 1 - P(no face) = 1 - 40C3/52C3 = 0.5529
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b) exactly one face card or one ace card (but not one of each)
(40/52)(12C2/52C2) + (4/52)(48C2/52C2)
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c) exactly two face cards
12C2/52C2 * 40C2/52C2
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d) one spade, one heart, one diamond
(4/52)(4/48)(4/44)
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e) at least one face card or one club
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Cheers,
Stan H.