Question 656266
{{{6/(x-4)=(x-3)/(x+2)}}}

Cross multiply:

6(x+2) = (x-3)(x-4)

6x+12 = x²-7x+12

    0 = x²-13x
    0 = x(x-13)

Use the zero-factor property

       x = 0;  x-13 = 0
                  x = 13

There are two solutions, 0 and 13.

Edwin</pre>