Question 59685
The question is quite confusing because we need to know whether the radical is there for the entire expression that is, 

rs(4x + 12 + 4) or only for 4x + 12. 


I will solve them for you in both the ways.


1st METHOD


RS(4x+ 12 + 4) = 0

Taking square root on both sides of the above equation, we get: 

4x + 12 + 4 = 0

==> 4x + 16 = 0

Subtracting 16 from both sides of the above equation, we get: 

==> 4x = - 16

==> x = - 16/4

==> x = -4


2nd METHOD 


RS(4x + 12) + 4 = 0 

Subtracting 4 from both sides of the above equation, we get: 

==> RS(4x + 12)  = -4 

Now, Squaring both sides of the above equation, we get: 

==> (4x + 12) = (-4)* (-4) 

==> (4x + 12) = 16 

Now, Subtracting 12 on both sides of the above equation, we get: 

==> 4x = 16 - 12

==> 4x = 4

==> x = 4/4 

==> x = 1 

Hence the solution.