Question 59438
(x=2)^2=16  This is mis-typed  I answered it one time by changing the first= to-, this time, I'll change it to +.
{{{(x+2)^2=16}}}
{{{sqrt((x+2)^2)}}}=+\-{{{sqrt(16)}}} 
x+2=+\-4
x+2-2=-2+\-4
x=-2+\-4
x=-2-4 and x=-2+4
x=-6 and x=2
Happy Calculating!!!