Question 655193
If sec theta = 3 find the exact value of : 
a) cos theta
b) tan^2 theta
c) csc(90 degree - theta)
d) sin^2 theta
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for [0,2π]
sec theta=hypotenuse/adjacent side=3/1
opposite side=√(3^2-1^2)=√(9-1)=√8
a) cos theta=1/sec theta=1/3
b) tan^2 theta
tan theta=opp side/adj side=√8/1=√8
tan^2 theta=8
c) csc(90 degree - theta)=sec theta
d) sin^2 theta
sin theta=opp side/hypotenuse=√8/3
sin^2 theta=8/9