Question 655160
    A baseball is hit by Ordonez at an initial velocity of 145 feet per second. Using the equation of height versus time h= -16t^2+v0t+h0 , where h is height at a given time, v0 is initial velocity, and h0 is the initial height, 
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Assuming the initial height was 4 feet (chest level) then
Your equation is:
h= -16t^2+145t+4
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what is the maximum height the ball reaches assuming no wind resistance? 
max height is at the vertex:
t value at vertex:
t = -b/2a
t = -145/(2*(-16))
t = -145/(-32)
t = 4.53 sec
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height at that time is:
h= -16t^2+145t+4
h= -16(4)^2+145(4)+4
h= 328 feet
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How long does the ball stay in the air?
set h to zero and solve for t:
h= -16t^2+145t+4
0= -16t^2+145t+4
solving for t using the "quadratic formula" yields:
t = {-0.03, 9.10}
throw out the negative solution leaving
t = 9.1 seconds