Question 654643
I need help on this problem, "A triangle has a perimeter of 108 yards. The first side is twice the length of the second side. The third side is 8 yards longer than the second side. How long is each side?" 
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2nd side: x
1st side: 2x
3rd side: 2x+8
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x + 2x + 2x+8 = 108
5x = 100
x = 20 yds.
2x = 40 yds
2x+8 = 48 hds
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Cheers,
Stan H.