Question 654639
 A ladder is resting against a wall. The top of the ladder touches the wall at a height of 15 feet. Find the distance from the wall to the bottom of the ladder if the length is one foot more than twice its distance from the wall.
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Draw the picture.
You have a right triangle with height = 15, base = x ; 
hypotenuse = 2x-1
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Equation:
x^2 + (2x-1)^2 = 15*2
x^2 + 4x^2 + 4x + 1 = 225
5x^2 + 4x = 224
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5x^2 + 4x - 224 = 0
x = 6.3 ft (base)
2x-1 = 12.6-1 = 11.6 ft (length of the ladder)
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Cheers,
Stan H.
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