Question 654208
Find the remaining trigonometric ratios.
cos(x) = &#8722; 1/7, &#960; < x < 3&#960;/2
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you are working with a reference angle and right triangle in quadrant III
cos=-1/7=adj side/hypotenuse
opp side=-&#8730;(7^2-1^2)=-&#8730;(49-1)=-&#8730;48
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trigonometric ratios:
sin(x)=-&#8730;48/7
cos(x)=-1/7
tan(x)=&#8730;48
csc(x)=-7/&#8730;48
sec(x)=-7
cot(x)=1/&#8730;48