Question 654100

recall:

the first basic exponent rule: Whenever you multiply two terms with the same base, you can add the exponents:

        {{{( x^ m ) ( x^ n ) = x^( m + n )}}}


{{{3*9^(2n) = (3^(n+1))^3}}}


{{{3*(3^2)^(2n) = 3^(3n+3)}}}


{{{3^1*3^(2*2n) = 3^(3n+3)}}}


{{{3^(4n+1) = 3^(3n+3)}}}.... if bases same, exponents are same too

so, we have


{{{4n+1 = 3n+3}}}....solve for {{{n}}}

{{{4n-3n = 3-1}}}

{{{highlight(n = 2)}}}