Question 654048
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That's a big fat lie.  Let *[tex \LARGE x\ =\ -2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (-2)^2\ =\ 4\ \geq\ 1]


but


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -2\ \not\geq\ 1]


However,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ \geq\ 1\ \ \Rightarrow\ \ |x|\ \geq\ 1\ \forall\ x\ \in\ \mathbb{R}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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