Question 653903
{{{16t^2 - 48t = 0}}}


{{{16t(t - 3) = 0}}}


{{{16t=0}}} or {{{t - 3 = 0}}}


{{{t=0/16}}} or {{{t = 0+3}}}


{{{t=0}}} or {{{t = 3}}}


So the solutions are {{{t=0}}} or {{{t = 3}}}