Question 653878
Let a = the time required by Andrew to paint the house
Let b = the time required by Bailey to paint the house
Since Andrew works 5 times as fast, b = 5a
Working together, their rate (in houses per day) is:
1/a + 1/5a
And they take 9 days to paint the house -> their combined work rate = 1 house per 9 days = 1/9
1/a + 1/5a = 1/9
Solve for a:
5/5a + 1/5a = 1/9
6/5a = 1/9
a = 54/5 = 10 4/5 days
And Bailey would take 54/5*5 = 54 days