Question 653636
Given:
1) {{{x-2y = -2}}} and
2) {{{x+2y = 10}}}
Get both of these equations into the slope-intercept form: {{{y = mx+b}}}
1) {{{x-2y = -2}}} Add 2y to both sides.
1a) {{{x = 2y-2}}} Add 2 to both sides.
1b) {{{x+2 = 2y}}} Divide both sides by 2.
1c {{{(1/2)x+1 = y}}} or {{{highlight(y = (1/2)x+1)}}}
2) {{{x+2y = 10}}} Subtract x from both sides.
2a) {{{2y = -x+10}}} Divide both sides by 2.
2b) {{{highlight_green(y = (-1/2)x+5)}}}
Now graph these:
{{{graph(400,400,-5,5,-5,5,(1/2)x+1,(-1/2)x +5)}}}
Yes there is a solution and it's (4, 3)