Question 653416
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ -2]


is a vertical line through all points of the form *[tex \LARGE \left(-2,y\right)]


A line perpendicular to a vertical line is a horizontal line.  Horizontal lines are represented by equations of the form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ b]


Where *[tex \LARGE b] is the *[tex \LARGE y]-coordinate of any point through which the line passes.  So if your desired line goes through *[tex \LARGE \left(-6,\,2\right)], then the equation must be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ ???]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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