Question 653397
To find the equation of the line passing through the point (2, 2) and (6, 3), start by finding the slope using the slope formula:

{{{(y2 - y1)/(x2 - x1)}}}

Label the points given:

x1 = 2
y1 = 2
x2 = 6
y2 = 3

Substitute these values into the formula:

m={{{(3 - 2)/(6 - 2)}}}

Simplify

{{{1/4}}}

Now that we have the slope m = {{{1/4}}}, we will use the formula 

y - y1 = m(x - x1)

y - 2 = {{{1/4}}}(x - 2)

Multiply both sides by 4 to get rid of the fraction:

4(y - 2) = x - 2

Simplify

4y - 8 = x - 2

Add 8 to both sides:

4y = x - 2 + 8

Subtract x from both sides:

4y - x = -2 + 8

Simplify

4y - x = 6