Question 653300
Let the two equal sides of the triangular parking lot be x m
and the third side= x+5 m
Perimeter= 71m
Perimeter,P= x+ x+ x+5
 71 = 3x+ 5
 3x= 71-5
 3x= 66
 x= 66/3
 x=22m 
So two equal sides of the parking lot are 22m each and the third side is (22+5)=27 m