<PRE><B>Question 653285</B>
The box is a cuboid 
height,h=5 inches, width=w and length,l=w+3 inches
Volume = 350
Volume =l*w*h
       =(w+3)*w*5
       =5w(w+3)
       =5(w^2+ 3w)
 350 = 5w^2 +15w
 5w^2 +15w -350=0
Divide the equation by the H.C.F,5
 w^2 + 3w -70=0
 factors of 70= 2,5,7
 w^2 + 10w -7w -70=0
 w(w+10) -7(w+10)=0
 (w+10)(w-7)=0
 w=7,-10
the width of the cuboid cannot be negative ,so width is 7 inches and
length=w+3
    l=7+3=10 inches
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